How to list out the alphabets of a name using for loop in python

Question

Python

Answer 1

Please, explain your question better, and show your attempt. Else we can’t help you more 😐

Answer 2

Divya Dharsini Murugesan ,

your description is a bit vague, so please give sample of input and how the output should look like.

we already have 2 assumptions, and there could be an other one:

"testcases" => {'t': 2, 'e': 2, 's': 3, 'c': 1, 'a': 1}

Answer 3

Ugulberto Sánchez ,

the only thing we can do for the moment is guessing, what we should avoid.

the op is expecting helpful hints, so we can expect a proper description and the code attempt from him - right?

Answer 4

If you mean ordering a list of strings or other datatype:
[“hello”, “abc”, “sololearn”]
Use sorted() function:
sorted([“hello”, “abc”, “sololearn”] -> [“abc”, “hello”, “sololearn”]

Answer 5

Why not just do:
name = input() #Take the name as a string
alphabet_list = list(name) #transforms name into a list of characters
print(alphabet_list) #Print it to the output.

Or just one line of code:
print(list(input()))

Answer 6

name = "John"
alphabet_list = [i for i in name]
print(alphabet_list)

Explanation:
>> name = input()
This line of code prompts the user to enter a name and stores the input value in the name variable.

>> alphabet_list = [i for i in name]
This line of code uses a list comprehension to create a new list called alphabet_list. The list comprehension iterates through each character i in the name string and appends it to the alphabet_list list.

>> print(alphabet_list)
This line of code outputs the alphabet_list to the console.

Input: John
Output: ['J', 'o', 'h', 'n']

Answer 7

Lothar so just wait 😐

Answer 8

Divya Dharsini Murugesan What in the world is an alphabet of a name?