Age

Question

#include <iostream>
using namespace std;

int main() {
//your code goes here
int age;
cin >> age;
if (age>=16)
{
cout << "welcome";
}
else
{
cout << "Not allowed";
}
}

Answer 1

Check the spelling of the output. It must be exactly like in the task description

Answer 2

Check the task's description for the outputs must be the same as described.

#include <iostream>
using namespace std;

int main() {
//your code goes here
int age;
cin >> age;
if (age>=16&& age <=60)
{
cout << "welcome";
}
else
{
cout << "not allowed";
}
}

Answer 3

BlunderKing Please read the thread before you paste your answer here.

Answer 4

What are you trying by this code?

when if age >= 16 false then age >= 60 also always false..

Answer 5

MMK recheck your reply, it is missing values for the age!
If the task is :
If age >= 16 then output "Welcome" Else print "not allowed" then your code works fine. But just check output statements spelling from the task description. There "Welcome", capital W but you using small w.
"not allowed", all small case but your code has capital N.

If there need to check age <= 60 then add this as nested if condition or by compound condition by using &&. Like :
if ( age >= 16 && age <= 60 )

Hope it clears....

Answer 6

If the user enters 63, then 63 is greater or equal 16. The second else if will not be reached.

Answer 7

MMK What is the task actually?
Add description here..

Answer 8

What is the code supposed to do?

Answer 9

greater or equal than what?

Answer 10

Lisa thank you so much... It done
I written allways "welcome" but it is "Welcome"

Answer 11

Great that you could solve it!

Answer 12

How can i solve this

Answer 13

#include <iostream>
using namespace std;

int main() {
int age;
cin >> age;
if(age >= 16) {
cout << "welcome";
}
else {
cout << "Not allowed";
}
}

Answer 14

Take the client age as a input, then show output "Welcome" if age is greathear or equal to 16. If it’s not show "not allowed".

Answer 15

I tried many way but it’s not working, maybe it is bug from sololearn.

Answer 16

Client age should be 16 plus, to output "welcome"

Answer 17

Ok

Answer 18

Thanks all, for your response....