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Having trouble with easy kaleidoscope challenge

I'm trying to practice and get better at programming by doing the challenges i need assistance with one of them I feel like I'm close to solving it but can't figure it out Kale is price of kaleidoscope, buy is how many is being bought, tax is the 7% tax, and no_dis is no discount if user buy 4 they get a 10% discount def purchase(kale, buy, tax): no_dis = kale * buy + tax if buy == 4: no_dis / 10 return no_dis x = 5 y = int(input()) t = x * 0.07 tax = t + x result = purchase(x, y, tax) print(result)

31st Aug 2023, 12:30 AM
Marshall Lance Freeman
Marshall Lance Freeman - avatar
1 Respuesta
+ 6
Marshall Lance Freeman , here some hints you may follow: the current code is quite difficult to read and understand, because calculation and logic is split up in main program and a function. ● the basic task is to check if a discount can be given or not.● > if the number_of_items purchased is greater than 1: give discount > else give NO discount try to simplify also the calculation itself. if discount can be given (eg 3 items are purchased): number_of_items * price_per_item * discount * tax >>> 3 * 5 * 0.9 * 1.07 if discount can not be given (eg 1 item is purchased): number_of_items * price_per_item * tax ... the final output should be rounded to 2 decimal places
31st Aug 2023, 2:19 PM
Lothar
Lothar - avatar