How to output only even numbers? Given that x = 0 while x<=10: print(x) x+=1

Question

Please help me to output only even numbers

Answer 1

x=2
while x<10:
x=x+2
print(x)

This is the easiest way out of all.

Answer 2

your indentation is wrong.
your code runs from x = 0 up to x = 10, then the while loop is finish. after that comes the if part, with x = 11 and thatsway you don‘t get the even nums.

thats the rigth way. the if condition is part of even while loopand prints the even nums.

x = 0
while x<=10:
#print(x)
x+=1
if (x%2) == 0:
print(x)

Answer 3

You can use the remainder (%)

if(x%2==0) {
// print x
}

Answer 4

x = 0
while x<=10:
if (x % 2) == 0:
print(x)
x+=1

Answer 5

It's while loop lesson code. Have you done it??

Answer 6

Then you are doing something wrong, it will only print even numbers. Ofc i know the while loop is the same for all languages..

Post your code

Answer 7

Wait I'll do

Answer 8

x = 0
while x<=10:
print(x)
x+=1
if (x%2) == 0:
print(x)

Answer 9

It is in python??

Answer 10

Almost the same.. use this

if (x%2) == 0:

Answer 11

No it's output is
1
2
3
4
5
6
7
8
9
10

Answer 12

I don't know how to output only even numbers this code output all numbers 1 to 10

Answer 13

Thanks for your answers I have done it.

Answer 14

print(*[i for i in range(2,11,2)])

Answer 15

Java

Int x = 0;
X<=10;
X++;
If (x%2==0){
System.out.println("x is even")
}