Answer 1

@Lisa I did that already by using isalpha().
Anyway, I found the problem. The conditional block I used, doesn't account for the case when the input string ends in in an alphabetic character.
Fixed this by adding

```
if count > 0:
lengths.append(count)
```

outside the for loop. It passes all the test conditions.
I wonder if there's a more efficient way to code this.

Answer 2

The instruction asks you to "Remove all punctuation."