Whether no. is even or odd. What's wrong in this code?, why it's showing an error?

Question

# A program to check if a number entered by user is odd or even
num = int(input("enter your number: "))
if (num % 2 == 0):
print("even")
else:
print("odd")

Answer 1

The lines where `if` and `else` was written was indented. Those lines should be at the same indentation level with the line where input() was invoked (first line of code).

Answer 2

Remove brackets in the if statement :).

num = int(input("enter your number: "))
if num % 2 == 0:
print("even")
else:
print("odd")

Answer 3

Oh okayy😅

Answer 4

Ipang Yeah, you are right. There is a slight indentation that Python does not like :D

Answer 5

Dw, I had a same problem, because i am used to Java lol

Answer 6

Yeah I tried it even by removing parentheses but it is showing error.

Answer 7

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Answer 8

To hard

Answer 9

'''
old

copy this reply into the code (remove code first) if it dont work then dont save changes.

# A program to check if a number entered by user is odd or even
num = int(input("enter your number: "))
if (num % 2 == 0):
print("even")
else:
print("odd")

new

'''

num = int(input("enter your number: "))
if num % 2 == 0:
print("even")
else:
print("odd")

'''

explanation

so basically, the code you written.

num = int(input("enter your number: "))
==> if (num % 2 == 0):
print("even")
==> else:
print("odd")

the arrows point to the indents.

updated code:

num = int(input("enter your number: "))
if num % 2 == 0:
print("even")
else:
print("odd")

oh and the parentheses I forgor about those

anyways copy this text and paste it into the code (remove the old one)
see if it works

'''

Answer 10

TRY THIS ONE ......
You may change the int numb from 5 to somethimg else it will work

int num = 5;
if (num % 2 == 0){

System.out.print("even");
}
else{

System.out.print("odd");
}
}
}