Doubt in C

Question

#include <stdio.h>

int main() {
int a, b, c;

for(c = 1; c < 9; c++){
printf("\n");
if (c % 2 == 0){
for(b = 0; b < 4; b++){
printf("⬜️⬛️");
}
}
else{
for(a = 0; a < 4; a++){
printf("⬛️⬜️");
}
}
}
printf("\n Lets Play!");

return 0;
}
.
.
.
Ques: if(c%2==0);
What does this line mean? Why c% ?

Answer 1

it can be simpler:

#include <stdio.h>

int main() {
for(int i=1; i<9; i++){
if(i%2==0)
puts("⬜️⬛️⬜⬛⬜⬛⬜⬛");
else
puts("⬛️⬜️⬛⬜⬛⬜⬛⬜");
}
puts(" Lets Play!");
}

Answer 2

c%2==0 is a way to check if c is even. c=0, 2,4,6,8
This is so that we can alternate between printing
⬜⬛⬜⬛⬜⬛⬜⬛ if(c%2==0)
and
⬛⬜⬛⬜⬛⬜⬛⬜ (else)
to print the checkerboard pattern