Can anyone explain the following code

Question

Got this code in a challenge. But I'm not able to connect the logic. Can anyone please explain.
https://code.sololearn.com/cooTD3Aj344F/?ref=app

Answer 1

int[] n={0,1,0,-1};

// loop over the array,
// starting at the 2nd value
for (int i=1;i<n.length;i++) {

// if the element is zero
// and the element before it is not zero
if(n[i]==0 && n[i-1]!= 0){

// assign the value of the element
// before this to x
int x= n[i-1];

// assign the actual element's value
// to the element before it
n[i-1]= n[i];

// assign the value of x to the
// actual element
n[i]= x;

// print the third element of the array
System.out.print(n[2]);
}

Answer 2

The if statement is only true for the 3rd element of the array.
So,
x is 1
n[1] is set to 0
n[2] is set to x which is 1.
1 is the output.

Answer 3

You're welcome.

Answer 4

You mean the whole array?
for (int i : yourArray)
System.out.println(i);

Answer 5

https://code.sololearn.com/cwzsgA8l1FJ9/?ref=app

Answer 6

Yes. I forgot. Printed it using this

for( int j=0;j<n.length;j++){
System.out.print(n[j]) ;
}

Thanks.

Answer 7

Ok thanks a lot Tashi. That helped. Could you help me out with one more thing. What do I have to do to print the new array? Thanks in advance