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I cannot understand the role of the line "AddOneTo(x)" here.
4 Respuestas
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your basically adding one to your factor thats in the ( ). how it works, idk.
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you run the void AddOneTo(); and you take the variable x to make it work with the integer number that equals. So when you run AddOneTo(x); you run this void with the variable x and this integer increments by 1.
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so why doesnt it print the incremented value, is it predefined that values will not be incremented and if it is why is it so?
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When I read it, I thought it would take 5 and add 1 to give you 6