Can anyone help me a program that calculate sum of n^10 from 2 to 10

Question

sum of n^10 from 2 to 10

Answer 1

#include <iostream>
#include<cmath>
using namespace std;

int main()
{
float sum = 0;
for(int i = 2; i <= 10; i++){
sum +=pow(i, 10);
}
cout << sum;
}

Answer 2

include cmath, then call the pow function within a for loop