- 11
What the answer
Fill in the blanks to print "Yes" if the list contains 'z': what's the answer letters = ['a', 'b', 'z'] _ "z" _ letters: print("Yes")
37 Respuestas
+ 6
list.append ('z')
print( len (list) )
+ 3
the ans is
if "z" in letters:
print("Yes")
+ 3
Fill in the blanks to create a set, add the letter "z" to it, and print its length.
nums =
{
"a", "b", "c", "d"
}
nums.
add
("z")
print(
len
(nums))
+ 2
If"z"in
+ 2
Fill in the blanks to create a stack of integers and push 11, 42, and 15 to it. Print "yes" if the stack contains 42.
Stack<int> st = new Stack<
int
>();
st
.Push(11);
st.Push(42);
st.Push(15);
(st.Contains(42)) {
Console.WriteLine("yes");
}
What is the answer?
+ 2
Stack<int> st = new Stack<
int
>();
st
.Push(11);
st.Push(42);
st.Push(15);
if(st.Contains(42)) {
Console.WriteLine("yes");
}
+ 1
Thanks to Makhan
+ 1
la respuesta es if y en el otro recuadro va in
+ 1
1. if
2. in
0
Drag and drop from the options below to add 'z' to the end of the list and print the list's length.
list. ('z')
print( ) )
insert len append (list) index.
What go in the gap
0
list.append ('z')
print( len (list) )
0
void print(int n) {
if (n < 0) return;
printf("%d", n);
print(n - 1);
}
0
Заполните пробелы, чтобы напечатать "да", если список содержит 'z': буквы = ['A', 'b', 'z']
"Зет"
буквы:
печать ("да")
0
letters = ['a', 'b', 'z']
if "z" in letters:
print("Yes")
0
letters = ['a', 'b', 'c']
for
l
in
letters
:
print(l)
0
can you please try the following
letters = ['a', 'b', 'z']
if
"z"
in
letters:
print("Yes")
0
The answer is
if "z" in letters:
0
0
Fill in the blanks to create a set, add the letter "z" to it, and print its length.
nums =
{
"a", "b", "c", "d"
}
nums.
add
("z")
print(
len
(nums))
0
: )