How the following code results in false output?

Question

public class Program
{
public static void main(String[] args) {
boolean v = (true||!(!false ))?false:true ;
if(false){
v=true;

}
else {
v=v==true;
}
System.out.print(v);
}
}

//What is v=v==true?

Answer 1

Line 1:- boolean v = (1) ? (2) : (3)

means if 1 is true, then assign v =2, else v=3.

For your line , 1 is true, hence 2 is assigned, 2 is false.

Hence v is false

if(false) is never gonna run,
else will run

v=v==true;

this is same as
v = (v == true);

that is, if v==true , then assign v as true, else assign it false.(== returns either true or false)
since v is false and false == true is false , v==true is false .hEnce v is assigned false.

Answer 2

at boolean v. v is false
if and else. execute else v = (false==true) now v = false
System.out.print(v) Search value v and v is false print false

Answer 3

Anytime @Prathamesh

Answer 4

Thanks Singh... That helped