+ 4

sort two lists accordingly

So I have recentely made a text analyser, but I want the output to be alphabetical without changing the order of list1. So does anyone know a way to sort the output of this code? Here follows the code text=input() list1=["e", "t", "a", "o", "i", "n", "s", "h", "r", "d", "l", "c", "u", "m", "w", "f", "g", "y", "p", "b", "v", "k", "j", "x", "q", "z"] list2=[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 ] for char in (text): for i in range(26): if char==list1[i]: list2[i]+=1 break continue for i in range(26): if list2[i]!=0: print("ammount of "+str(list1[i])+"\'s: "+str(list2[i]))

10th May 2017, 3:51 PM
Daan van IJcken
Daan van IJcken - avatar
3 Respuestas
+ 5
I tried to make code that does not use a dict. for alphabet in [chr(i) for i in range(97,97+26)]: x = list1.index(alphabet) if list2[x] != 0: print("ammount of " + list1[x] + "\'s: " + str(list2[x]))
10th May 2017, 5:35 PM
Suyasa
Suyasa - avatar
+ 4
text = input() list1 = ["e", "t", "a", "o", "i", "n", "s", "h", "r", "d", "l", "c", "u", "m", "w", "f", "g", "y", "p", "b", "v", "k", "j", "x", "q", "z"] list2 = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 ] for char in (text): for i in range(26): if char == list1[i]: list2[i]+=1 break continue d = dict(zip(list1, list2)) for alphabet in [chr(i) for i in range(97,97+26)]: if d[alphabet] != 0: print("ammount of " + alphabet + "\'s: " + str(d[alphabet]))
10th May 2017, 4:53 PM
Suyasa
Suyasa - avatar
+ 2
I think it is better to use dictionary. Then the code can be changed like following: text=input() dict={} for char in text: if char in dict.keys(): dict[char]+=1 else: dict[char]=1 for x in range(ord('a'),ord('z')+1): if chr(x) in dict.keys(): print("amount of "+chr(x)+"\'s: "+str(dict[chr(x)])) I'm sorry I use python 2. I hope it works on 3 too.. It will show the number of characters in alphabetical order
10th May 2017, 4:20 PM
OrbitHv [Inactive]
OrbitHv [Inactive] - avatar