Guess the output of this expression.i=1;

Question

cout<<++i<<i++;

Answer 1

right, how about this?

unsigned long long x=12345678912345678912;

unsigned long long
y=123456789123456789123;

unsigned long long
z=1234567891234567891234;

cout<<x<<endl;
cout<<y<<endl;
cout<<z<<endl;

Answer 2

Is it because of long long type over-flow ?

Answer 3

The range of unsigned long long int is
0 to 18,446,744,073,709,551,615.
If it exceeds limit value , it will be truncated.

Answer 4

Wrong answer

Answer 5

1043

Answer 6

😱😱😱😨😨

Answer 7

can you explain it ?

Answer 8

How ?

Answer 9

it's 31

Answer 10

anytime !! 😃

Answer 11

yes please

Answer 12

now how about this?
what is the output ?
no codeplayground, please.

char a[]="";
char b[]="C++";
cout <<sizeof(a)<<endl;
cout <<strlen(a)<<endl;
cout <<sizeof(b)<<endl;
cout <<strlen(b)<<endl;

Answer 13

@Setiawan
Well, your code is full of wisdom. I like it so much.
Please explain to me..

Answer 14

@prabhu
yes, it is. that cause undefined behaviour.
the output is depent on compiler.

Answer 15

This is what @Calvin told me :
"You have reached the edge of the Universe."
😃😃😃

Answer 16

you right, thank for the lesson.

Answer 17

use codeplayground

Answer 18

well, calvin explained to me. i can explained to you if you want.

Answer 19

Lol @Setiawan, you still remember..😂

Answer 20

22