ques 1. int y = 5; cout<< ++y + y++; ques 2. int y = 5; cout<< y++ + ++y; how is it working?

Question

output of 1 is 13 and output of 2 is 12

Answer 1

i explored Internet and i found that post increment has higher precedence than pre increment. I hope that's the correct explanation, if we apply this to questions the answers come correct.

Answer 2

in ques 1 ++y will be 5+1 as ++ increment are before. now ++y=6 then you are adding y to it as (++y +y)++ according to c++ so 6+6=12 then one ++ increment to the answer hence 13

Answer 3

but in ques 2 y++ will be treated as 5 becoz you are incrementing ++later then you are adding ++y as y has become 6 ++ before will make it 7 so answer is 5+7=12

Answer 4

This question baffles me.. Cheers to Mr Preet Singh for asking this...

Answer 5

The question is really tricky and almost impossible to answer. The reason is behind the find of Pahul Preet Singh. Yes, precedence is a keypoint, meanwhile the implementation how precedence handled by compiler are differ from compiler to compiler. That's why the same code will outputs different results in different environments. For example, Sololearn has 13 and 12, MS Visual Studio 2015 has 12 and 12.
To avoid this, it's recommended to not alter an output more than once in a statement. For example, use x = 1 + x except x = ++x.

Answer 6

the result may be different depending on the compiler, and even may differ from version to version. Agree with Tamas to write clean code, not alter output more than once, and it may be confusing.

Answer 7

No idea