Please someone expain me how this happens. 😊

Question

int p=8;
cout <<p++;
cout << ++p;

//output 810

Answer 1

cout << p++;

// The value of p is used, before incrementing
// 8 is printed
// then value of p becomes 9

cout << ++p;

// the value of p is incremented, and then used
// value of p becomes 10
// 10 is printed

// 810

Answer 2

you have to understand prefix and postfix

https://www.sololearn.com/discuss/452566/?ref=app

https://www.sololearn.com/discuss/452566/?ref=app

https://www.sololearn.com/discuss/427611/?ref=app

Answer 3

1)cout << p++ will display the output of p first and then increase the value of p by 1

so now value of p is 9..and output is 8

2)cout << ++p will increase the value of p first and then then it will display output...so here value of p will be 9+1=10...

considering both the steps...the output will show you 810...

Answer 4

@Hatsy Thank you very much. 😊😊😊😊

Answer 5

@chirag thank you. yeah. I have some doubts with them.

Answer 6

@Prahar thank you😊

Answer 7

@pratik thank you👌

Answer 8

p++ is prefix. means it print the value of p first and than increment tha value of p. so as shown in your output it print 8 first and than it increment. so now p=9.

and in next line of code ++p is post fix so it increment the value of p and than print. so value of p is 9 which increment first and than print so as shown in your output is 10 after 8.

8 and 10.