Fill in the blanks to create a new set "c", with only the values common to both "a" and "b", if not all of the values of set "a"

Question

I DONT UNDERSTAND

Answer 1

Fill in the blanks to create and output a set with the values 1, 2, 3.

const set =

new

Set();
set.add(1).add(2).

add

(3);
for(let v of set.values())
console.log(

v

);

Answer 2

All values of Set A are contained in Set B means --> A is a Subset of B.
a.Subset(b)

In question, we need the reverse condition --> A is not a Subset of B.
So, the condition becomes :

if ! a. Subset(b) {
}

Then, we need values common to both sets A & B ==> Intersection of sets A & B.
So, the entire code snippet becomes:

if ! a. Subset(b) {
let c: = a. intersect(b)
}

Answer 3

Fill in the blanks to create a new set "c", with only the values common to both "a" and "b", if not all of the values of set "a" are contained in set "b".
let a: Set = [1, 2, 3]
let b: Set = [3, 5, 2]
if ! a. (b) {
let c: isSubsetOf = a. (b)
}

I don't understand

Answer 4

Fill in the blanks to create and output a set with the values 1, 2, 3.

const set =

new

Set();
set.add(1).add(2).

add

(3);
for(let v of set.values())
console.log(

v

);

Answer 5

new
add
v

Answer 6

thanks :)

Answer 7

Fill in the blanks to create and output a set with the values 1, 2, 3.
const set =

Set();
set.add(1).add(2).

(3);
for(let v of set.values())
console.log(

);

Answer 8

1. subset
2. set
3. intersection

Answer 9

onst set =
new
Set();

set.add(1).add(2).
add
(3);

for(let v of set.values())

console.log(
v
);

Answer 10

new
add
v

Answer 11

Fill in the blanks to create and output a set with the values 1, 2, 3.

const set =
new
Set();
set.add(1).add(2).
add
(3);
for(let v of set.values())
console.log(
v
);