Can someone explain to me how the answer to the code below is 300.

Question

def f(n):
if n == 0:
return 0
else:
return f(n-1) + 100

print(f(3))

Answer 1

f(3) = f(3-1) + 100 = ?

But what's f(3-1)?

f(3-1) = f(2-1) + 100

But what's f(2-1)?

f(2-1) = f(1-1) + 100

But what's f(1-1)?

f(0) = 0.

Therefore,

f(2-1) = f(1-1) + 100 = 100

f(3-1) = f(2-1) + 100 = 200

f(3) = f(3-1) + 100 = 300

Output: 300

Answer 2

thank you for the clarification