+ 1
Why are the results different?
#include <iostream> using namespace std; int main() { int i=3; int b=4; cout<< ++i + b++; return 0; } Result is 8. #include <iostream> using namespace std; int main() { int i=3; cout<< ++i + i++; return 0; } Result is 9. Why are the results different?
2 Respuestas
+ 11
In the first case, i is incremented prior to statement evaluation, while b is incremented after statement evaluation. During evaluation, i is 4 and b is 4. Outputs 8.
As for the second case, it has a catch.
https://stackoverflow.com/questions/4176328/undefined-behavior-and-sequence-points
+ 1
case 1:
i=3;
b=4;
cout ++i (prefix) mean it will increase 1 that mean 4;
b++(safix)that mean it will increase after , practical it will be in the same position b=4 in this situation
so the answer is 8;
second case:
i=3
++i mean (prefix) 1 increment
i++ mean (safix) remain at the same position in this situation.
so actually the answer in addition we get 7 not 9.