How do I find the percentage of characters in a text based on the users input.

Question

Character Percentage

Answer 1

Sure, I did it in C++ though, I commented in case you don't know it + I didnt feel like posting in the playground :):

#include <iostream>
#include <array>

int main()
{
// Array: A = index 0, B = index 1, ..., Z = index 25
std::array<int, 26> characters;
characters.fill(0);

// Counter
int counter = 0;

// String to process
std::string s = "How do I find the percentage of characters in a text based on the users input?";

// for each char in s
for(const auto& i : s)
{
// isalpha checks for alphabetic character
if(isalpha(i))
{
// Increment counter
++counter;

// Convert all characters to uppercase, to create case insensitive
// and since A = 65, we subtract 'A' to get the proper index.
// 'Z' - 'A' would be 25 :)
// and then increment that index by 1
++characters[toupper(i) - 'A'];
}
}

{

int x = 0;

// Iterate through the array
for(const auto& i : characters)
{
// counter ? (true) : (false) = check if counter is anything but 0
// I have to convert the int to float to get floating point division
// Anyway, divide the number by the counter and then * 100 = percentage

float percentage = (counter ? static_cast<float>(i) / counter * 100 : 0);

// Output
std::cout << static_cast<char>(x++ + 'A') << ": " << percentage << '%' << std::endl;
}
}
}

Answer 2

Now I understand. Thanks

Answer 3

Lets say we want to keep track of a-z and don't care if they are upper or lowercase.

1.
You will start with an array of 26 integers all initialized to 0
And another counter which keeps track of the total characters found.

2.
You then iterate over the string and you check if the character is a character you want to check for and if it is you increment the corresponding index in the array and the counter by 1

3.
You iterate over the array and divide the number by the total characters found ( beware of 0 division in edge cases ) and multiply that result by 100 to get the percentage.

4.
Done :)

Answer 4

A bit confused after instruction 2. Could you show that in code