To print the sum of tje following series-. S=a/1+a/2+a/3+....+a/n.

Question

please tell me the code

Answer 1

Each time, I consider a and n already declared
Python :
S = 0
for i in range(1,n+1):
S += a/i
print(S)

C/C++ :
double S = 0;
unsigned i;
for(i = 1; i <= n; ++i)
S += 1.*a/i;
//C++ : cout<<S<<endl;
//C : printf("%f\n",S);

Ruby :
s = 0 #capital letter is for constant
for i in 1..n do
s += a/i
done
puts a

Answer 2

Python : sum([a/(1+n) for n in range(n)])