why 1: False in output?

Question

pairs = {1: "apple",
"orange": [2, 3, 4],
True: False,
None: "True",
}

print(pairs.get("orange"))
print(pairs.get(7))
print(pairs.get(12345, "not in dictionary"))
pairs [2]=55
print (pairs)

output:

[2,3,4]
None
not in dictionary
{1:False , 'orange': [2, 3, 4], True: False, None: 'True',2:55}

Answer 1

Look in the comments; it helped me here and I think it'll help you too. ;)

Answer 2

IN PYTHON THIS THINGS ARE BY DEFAULT..

1 MEANS TRUE
0 MEANS FALSE

suppose...u doing
pairs={1 : "yoo" , 0 : "solo" ,True : "hi" , False : "bye"}

print(pairs)

{ 1 : "hi" , 0 : "bye" }

taking last values initialised in 1 and 0
as 1 is true and 0 is false
initialising in true and false means reinitialising in 1 and 0

Answer 3

### another proof that 1 is True and 0 is False####

try this code
###############
pairs={1 : "qwerty" , 0 : "solo"}

print(pairs.get(True))
print(pairs.get(False))
###############
output--->

qwerty
solo

Answer 4

thank you so much👌👌👌