6th Oct 2016, 8:22 AM
sabreen anjum
sabreen anjum - avatar
2 Respuestas
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import java.util.LinkedList; public class MyClass { public static void main(String[ ] args) { printNum(5); } public static void printNum(int n){ if(n==1) { System.out.println(n); }else{ printNum (n-1); System.out.println(n); } } } This application starts with printNum with value 5. Let's trace the function. there is a condition statement. If 5==1 False Else //here in else bracket, printNum (4) is called. Then let's start printNum with value 4. if 4==1 False Else //Again here. ... then you'll reach at printNum (1). If 1==1 True Yeah! then program prints out 1. (value of n) then this function ends. In printNum (2), Else printNum (1) was done. So next statement works. This prints out 2 (value of n) Again, this function of printNum (2) finishes, system reads next line of printNum (3), which called printNum (2) in Else. ... Therefore the result is 1 2 3 4 5
6th Oct 2016, 12:38 PM
Kim MinKwan
Kim MinKwan - avatar
0
Thanks @kimminkwan
7th Oct 2016, 2:55 AM
sabreen anjum
sabreen anjum - avatar