I want to get the average in double and the output must be 50.5. How do I get it and what's wrong with my code?

Question

public class Program
{
public static void main(String[] args) {
int sum=0;
double average =0;
int lowercase=1, uppercase=100;

for(int number = lowercase; number <= uppercase; ++number){
sum+=number;
}
System.out.println(sum);

for(double number = lowercase; number <= uppercase; ++number){
average +=number;
}
System.out.println(average);
}
}

Answer 1

Something like this...
public class Program {
public static void main(String[] args) {
int sum=0, count=0;
double average=0;

for(int i=1; i<=100; i++){
count++;
sum+=i;
}
average=sum/(double)count;
System.out.println("sum: "+sum);
System.out.println("count: "+count);
System.out.println("avg: "+average);
}
}

Answer 2

Thank you very much sir.. sadly I'm not skipping my math lessons, its just that I'm not that good in math either, but thank you very much I really appreciate it😊😊

Answer 3

@lpang
Why though?
There is no difference.
Both compile the same bytecode and are pretty much the same as far as readability/maintainability goes.
Doesn't really matter.

Answer 4

@Rrestoring Faith, I was referring to these lines (on the question):

for(int number = lowercase; number <= uppercase; ++number)
...

and these...

for(double number = lowercase; number <= uppercase; ++number)
...

I guess I'm much more accustomed to see post-increment in for loops rather than pre-increment. I'm sure you knew there are difference between the two, but yes, like you said, they are of the same, in this case, it's just a matter of preference.

Answer 5

Also in the for loop, please use post-increment instead of pre-increment, see @Tashi N answer for clarity of difference.

Answer 6

thank you for your answers people I don't know what to say but all thank you, thank you very much it help me alot