can any code check whether the input is integer or a String in Scanner

Question

any code ?

Answer 1

import java.util.Scanner ;

public class c{

public static void main(String[ ] args) {
Scanner n = new Scanner(System.in);
char c =n.next().charAt(0);
if(Character.isDigit(c)){
System.out.println("It's number");
}
else if(Character.isLetter(c)){
System.out.println("It's letter");
}
else
System.out.println("It's symbol");
}
}

Answer 2

So here's what I did.
Instead of using Scanner.nextInt() I used a simple next() to keep the information and not loose it. This means that I can use it again if needed.

Then I test each value if it can convert to an Integer, if so then it's a number, else it's just a string

https://code.sololearn.com/cMqAN0Xa2mNB/?ref=app

Answer 3

Well, there are methods for that in java. If you write sc.nextInt() it will get an integer type, and if you type sc.nextLine() it will get a string

Answer 4

Indeed,the problem is when we use scan.nextInt() and it throws an exception, you lose that data

Answer 5

java

Answer 6

nice, so then you just plug that into a for loop and test each character, if all characters are digits, then it's an Integer

Answer 7

yes .isDigit() and .isLetter() method of character using array code can easily do this

Answer 8

in which language?