Boolean logic and loops

Question

When does Boolean logic apply to an if loop? I'm certain I've seen it applied before, but in the following code it's not applicable:
#include <iostream>
using namespace std;
int x = 1;
int y = 1;
int main() {
if (x + y == 1) {cout << "It worked"<<endl;}
else cout << "It didn't work" << endl;
return 0;
}

Answer 1

The code works perfectly.

1 + 1 is 2 and 2 is clearly not 1. The code outputs "It didn't work".

Answer 2

First of all, if statement isn't a loop - it's a conditional statement like the switch.
Whatever you put in an if statement, boils down to a boolean "true/1" or "false/0" value.
For example:

// Example program
#include <iostream>
#include <cmath>
using namespace std;

int main() {
int a = -1;
int b = 128;
int c = 0;

float d = 1.45f / 98.0f;

double e = (2.71 + 3.14) * 30.0;
double f = sin(e);

char g = 'H';
long long h = 12345678912345;

if (a) cout << "a Done.\n";
if (b) cout << "b Done.\n";
if (c) cout << "c Done.\n";
if (d) cout << "d Done.\n";
if (e) cout << "e Done.\n";
if (f) cout << "f Done.\n";
if (g) cout << "g Done.\n";
if (h) cout << "h Done.\n";
}

https://code.sololearn.com/chAYAQ13fHDD

Answer 3

So give up vote to all friend who clarified the point for you, my friend.

Answer 4

Thanks dear Hatsy for useful tip. really worth to put it in my tutorial series.

@~)~~~~

Answer 5

Indeed, anything which is not 0 and not false is evaluated to true in C++, but in

if (1 + 1 == 1)

All the values are taken as integer values. Hence LHS and RHS value does not tally, and the statement is evaluated as false. Try doing

if (bool(1 + 1) == true)

// or

if (bool(1 + 1) == 1)

These will yield different results.

Answer 6

Also, the 'if' keyword is associated with conditional statements. There is no such thing as 'if loops'.

Answer 7

if (x+y==1) comes the boolean

Answer 8

I think boolean logic will not work here so here, 1+1==2 and not 1 as both the 1's are taken as decimal numbers, not binary numbers. So if statement doesn't executed and it shows "It didn't work".

Answer 9

Okay, I got confused because if I write something like
"int i =5;
if (i == 5)" this evaluates to
if (true)."
I thought that in this case as long as the number was anything other than 0 the code would consider the statement true, as in boolean logic, but this is not the case. It checks the condition truthfully, then the answer becomes 1 (true) or 0 (false).
Thanks.

Answer 10

First up, if statement is not a loop...

It will execute when the condition is true, and not when it is false.

if is a conditional statement.

Answer 11

True. If-statements

Answer 12

true if statement..

Answer 13

Boolean logic