how do I do that if I pass by a parameter 50, I get a random number between 1 and 50?

Question

class Random

Answer 1

import java.util.Random;

public class Program
{
static int rnd(int range)
{
Random obj = new Random();
return (1 + obj.nextInt(range));
}
public static void main(String[] args)
{
for (int i = 0; i < 100; i++)
System.out.println(rnd(50));
}
}

Answer 2

Assuming @Hasty's code is what the original question is referring to:

"System.out.println(rnd(50));"

Will print to the console whatever the rnd() method returns. With 50 being passed as arguments.

"return (1 + obj.nextInt(range));"

range will be the 50 that was passed as arguments.
So this is equivalent to:
return 1 + obj.nextInt(50);

nextInt() will return a pseudo random integer based on the number that was passed as arguments.
The number in this case being 50.

With 50, nextInt() is expected to return a number from 0-50.
*Note* 50 is exclusive. So, it's really from 0-49.
return 1 + (randNume from: 0-49)

Will now return a number from 1-50.
(Since the random number from 0-49 is added by 1)

So, a random number from 1-50 will be printed each time the line of code "System.out.println(rand(50));" is executed.

Answer 3

we can't read your mind, please explain what you mean by "that". Showing the code is also helpful.