I Challenge can anyone make the program below using only 2 loops and ifelse statements ..?

Question

1
121
12321
1234321
123454321
12345654321
123454321
1234321
12321
121
1

Answer 1

https://code.sololearn.com/cOaI43CDN1WV/#cpp
Two for loops and one if-else :) I had to add a bit of space around the diamond so the Code Playground doesn't mess up the output.

#include <cstdio>
#include <cstdlib>
#define P(c) putchar(c)
#define A(x) abs(x)
#define F(i) for(int i=-8;i<=8;i++)
#define R(x) return 0;

int main() {

F
(i)
{F(j)
{int a=
A(i)+A(j);
if(a>5)P(32)
;else P(54
-a);} P(
10);}
R()
;

}

Answer 2

Came up with my own solution as well:

#include <iostream>
#include <cmath>
using namespace std;

int main() {
int x, i, j, m = 5; // m = Max
for(i = -m; i <= m; i++) {
x = 0;
for(j = m; j >= -m; j--)
cout << (abs(i)<=m-abs(j) ?
(j<0?--x:++x) : 0);
cout << "\n";
}
return 0;
}

http://www.sololearn.com/app/cplusplus/playground/cvYHBj7gXPaG/

Answer 3

Great brother. I am just beginner to the c++. so I haven't thought this much. you are awesome.

Answer 4

what the hell.. did i just saw +schindlabua

Answer 5

it' s awesome you ask wish your future would be bright