+ 2

can anyone find error its showing cant find variable ki

package hdi; import java.util.Scanner; public class hdi { public static String pin(String x){ Scanner inp = new Scanner(System.in); System.out.println("Kindly input your number"); int ki = inp.nextInt(); Scanner inpu = new Scanner(System.in); System.out.println("kindly choose second number"); int kn = inpu.nextInt(); return ki; return kn; } public static void main(String[] args) {

2nd Oct 2017, 3:03 PM
Raghav Khullar
Raghav Khullar - avatar
1 Respuesta
+ 3
Raghav... notice on your method declaration that you are declaring that you are returning a string but variable ki and kn are of type int to fix this you can do the following: return new String(ki); or even this Interger [the class btw] ki = new Interger(inp.nextInt()); return ki.toString(); note there may be errors in this code since i did it from pure memory, look into the specifics of how to do this on google Continuing... you can only return one object. you cannot do return variable; return variable2; they both must be in the same array in order to return multiple values. so i recomend to do this public static String[] pin() { String[] arr = new String[2]; //scanner and printout code here int ki = inp.nextInt(); arr[0] = new String(ki); int kh = inp.nextInt(); arr[1] = new String(kh); return arr; } you will need to add the variable for the scanner and i did do this from memory so there may be some errors i hope this helps happy coding
2nd Oct 2017, 3:40 PM
SomeoneAwesome78
SomeoneAwesome78 - avatar