What is the highest number output by this code?

Question

I get a bit confused with this code.
What is the highest number output by this code?
def print_nums(x):
for i in range(x):
print(i)
return
print_nums(10)
To what I understand, range(10) would be 1 to 9 and the highest number should be 9, why it is 0?

Answer 1

anything after the "return" won't run , so it will go through the loop one time and exit it out, not 9 times

Answer 2

you have a return statement right after the print

the loop only prints 0 then returns

Answer 3

I get a bit confused with this code.
What is the highest number output by this code?
def print_nums(x):
for i in range(x):
print(i)
return
print_nums(10)
To what I understand, range(10) would be 1 to 9 and the highest number should be 9, why it is 0?

anything after the "return" won't run , so it will go through the loop one time and exit it out, not 9 times

Answer 4

That I understand return is as break there.
If you remove "return" and run it will count from 0 to 9.
If you add "break" instead of "return" the answer will be 0

Answer 5

0

Answer 6

0

Answer 7

0

Answer 8

it is o i did it

Answer 9

0

Answer 10

✔ 0

Answer 11

What is the highest number output by this code?
def print_nums(x):
for i in range(x):
print(i)
return
print_nums(10)

Ana: 0

Answer 12

What is the highest number output by this code?
def print_nums(x):
for i in range(x):
print(i)
return
print_nums(10)

Ans: 0

Answer 13

def print_nums(x):
for i in range(x):
print(i)
return
print_nums(10)

output: 0

Answer 14

What is the highest number output by this code?
def print_nums(x):
for i in range(x):
print(i)
return
print_nums(10)

answer= 0

Answer 15

0

Answer 16

3