Confusion, x++ is adding 1 when we apply this in loop,why?

Question

when we apply in loop, we write post increment x++ and postincrement add 1 after each cycle.
for(i=0; i<10; i++)
{
System.out.println("Why this i++ add 1");
}

Answer 1

i++ or ++i are equivalent (to i = i+1) when used as a standalone statement, which is the case here.

Post-incrementation doesn't mean that the incrementation isn't done.

Maybe your confusion stems from a wrong understanding of how a for loop works:
for(int i=0; i<10; i++) {
System.out.println(i);
}
is equivalent to:
int = 0;
while (i < 10) {
System.out.println(i);
i++;
}

Edit: Woops, thanks for the correction, Bobby.

Answer 2

Just so you are aware, Zen's information is correct however his syntax is for a different language. instead of cout<<i<<endl, use System.out.println(i);

edit: nevermind, he fixed it. :)

Answer 3

The difference in priority

Answer 4

it is because the program contains counting backwards