How does the dead monkey shows its tail?

Question

class Monkey {
public:
int taleLength = 3;
void showTale() {
cout << "Monkey says: 'My tale is " << taleLength << "m' \n";
}

~Monkey() {
cout << "Monkey was killed by a poacher :(\n";
}
};

int main() {
Monkey* p;

{
Monkey Jack;
p = &Jack;
}

p->showTale();
system("pause");
}

Output:
Monkey was killed by a poacher :(
Monkey says: 'My tale is 3m'

Destructor was called, but why does the Jack still exist?

Answer 1

Poor old Jack still exists and is valid because the stack has not been cleaned yet, nor has it been overwritten. Let's look at the partial disassembly:

#stack allocation and setting up stack frame
push rbp
mov rbp, rsp
sub rsp, 16

#Creating Jack on the stack
lea rdi, [rbp - 16]
call Monkey::Monkey()

#Get the address of Jack
lea rdi, [rbp - 16]

#Store it in p
mov QWORD PTR [rbp-8], rax

#Call destructor
call Monkey::~Monkey()

#Call showTale, p is still pointing to valid stack memory, so this will work.
mov rdi, qword ptr [rbp - 8]
call Monkey::showTale()

#deallocate stack and return 0
xor eax, eax
add rsp, 16
pop rbp
ret

Answer 2

I'm sorry, I don't know. But I definitely had to say this question's title made me laugh