Counting n numbers using C

Question

please help me by providing code for counting n numbers (ex- like o-9 displaying these numbers one by one by replacing it) using C

Answer 1

tanx for ur answer

Answer 2

#include <stdio.h>

int main(){
unsigned n, i;
unsigned long long sum = 0;

while(scanf("%u",&n) < 1)
puts("Bad input, try again (an unsigned integer)");

for(i = 1; i <= n; ++i, sum += i)
printf("i = %u\n",i);
printf("sum = %llu\n", sum);

return 0;
}

Answer 3

#include <stdio.h>
/* for the sleep function, unix dependant */
#include <unistd.h>

int main(){
unsigned n, i;

while(scanf("%u",&n) < 1)
puts("Bad input, try again");

putchar('\n');
for(i = 0; i <= n; ++i){
printf("\r%d",i);
fflush(stdout);
sleep(1);
}

return 0;
}

Answer 4

any c code ?

Answer 5

thank you for the code, but this is'nt the code that i want. i think you guys dont get my question.i will tell the program once more

A c program to Displaying n elements (ex 0-9) by overwriting the number itself.

Answer 6

#baptiste sir ,
ex- when i input 9 the program should print 0 -9 in one line. (1 st print 0 then overwright 0 with 1 then overright 1 with 2 .... upto 9

Answer 7

The numbers should print like a video with 1 or 2 second delay

Answer 8

I think u guys got what i mean.

Answer 9

#swim u comes close to it

but not this when i enter 4 it should print 0-4
first it should print 0, immediatly it should replaced by 1 and then replace 1 by 2 and so on upto 4

this should execute like a loop manner it should continuesly run

Answer 10

Obviously, my last solution (with sleep and fflush) does not work on sololearn

Answer 11

In which way, overwriting?