+ 3

Count vowel using pointer arithmetic

can we find number of vowels present in a given character array using pointer arithmetic

31st Oct 2017, 2:43 PM
Raj Gada
Raj Gada - avatar
1 Respuesta
+ 6
well I don't know too much about pointer algorithm but maybe this is how we do it : int main() { char *word = new char[250]; char *vov = {'a','e','i','o','u'}; cin.getline(word,250); int i,j,num_vov=0; for(i=0;i<strlen(word);i++) { for(j=0;j<5;j++) { if(word[i]==vov[j]) { num_vov+=1; } else { num_vov+=0 }; } } cout<<"\n Number of vowels = "<<num_vov; return 0; }
31st Oct 2017, 3:02 PM
RZK 022
RZK 022 - avatar