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count even and odd digits of the number

determine how many in the user input number of even number of odd

31st Oct 2017, 4:24 PM
Daniyar
2 Respuestas
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What issues have you run into while coding it? Id just go char by char and have an % 2 if else statement which would increment either first or second value and then print both of them
31st Oct 2017, 4:28 PM
imouse
imouse - avatar