Two pairs and two GCD

Question

What is wrong with this code?
#include<iostream>

using namespace std;

int main() {

int first_number;
cout<<"Enter First Number : ";
cin>>first_number;

int second_number;
cout<<"Enter Second Number: ";
cin>>second_number;

int third_number;
cout<<"Enter Third Number : ";
cin>>third_number;

int fourth_number;
cout<<"Enter Fourth Number: ";
cin>>fourth_number;

int gcd1;

for(int i=1;i<=first_number&&i<=second_number;i++){

if(first_number%i==0 && second_number%i == 0 ){

gcd1=i;

}
int gcd2;

for(int i=1;i<=third_number&&i<=fourth_number;i++){

if(third_number%i==0 && fourth_number%i == 0 ){

gcd2=i;
}
}

cout<<"Greatest Common Divison (GCD1):"<<gcd1<<endl;

cout<<"Greatest Common Divison (GCD2):"<<gcd2<<endl;

return 0;
}}

Why answer is 1 and 15, if first number is 9, second number is 27, third number is 15 and fourth number is 45? I suppose, there is very simple mistake.

Answer 1

Code looks good, but you have 2 closing brackets after return 0. Move one of them after first for loop, because there is missing closing bracket.