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How can I use "Math." To find the location of a digit in a large integer number?
I am trying to figure out how for example do I find the digit at location "2" (from the right! without 0) such as: In the number 12345 digit number 2 is 4. (in this specific problem) but how do I do it? Couldn't find a solution!
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Hey, thanks but I managed figured it out!
I used:
value = value / (int)Math.pow(10, location - 1) % 10 and it gave the index value.