Why the "Match2" can't be printed with the pattern r"(\D+\d)"?

Question

import re

pattern = r"(\D+\d)"

match = re.match(pattern, "1, 23, 456!")
if match:
print("Match 2")

Why the "Match2" can't be printed with the pattern r"(\D+\d)"? I thought there would be two sub-string that can be matched, ", 2" and ", 4"

Answer 1

The pattern r"(\D+\d)" matches only a string which starts with non-digit and then has a digit.
When you are use re.match it looks in the beggining of a string to find that pattern.
"1, 23, 456!" starts with a digit (1) and that's why it doesn't match the pattern.
But if you use re.search instead it will be a match.

Answer 2

Try using re.findall instead of re.match

Answer 3

@Tim
@Kuba

Thank you.I see. I forget that the "re.match" is just applied at the beginning of a string.