How to print 1 2 3 4 5 6 7 8 9 10 9 8 7 6 5 4 3 2 1 in C++ by using only one loop?

Answer 1

Here you can check my code for you
https://code.sololearn.com/cM22opxG0CyH/?ref=app

Answer 2

ok sorry I didn't paid attention! no reason to downvote like this..
be quiet bros!
what about this?

https://code.sololearn.com/cDA4szWAp6Xy/?ref=app

Answer 3

for(int i = 1; i < 20; i++){
cout<<(i > 10) ? 20-i : i;
}

Answer 4

and also.. who downvotes should enlight us whit a good answer!

Answer 5

@aztecco good, very good

Answer 6

@aztecco it's probably a crazy man))

Answer 7

You could always do it with no loops.
https://code.sololearn.com/cJjsg7x4c6ST/?ref=app

Answer 8

thank you @Robert! but I'm not crazy.. or not at all lol

Answer 9

@aztecco They require only one loop, but you wrote with two loops, try again

Answer 10

#include <iostream>
using namespace std;
int main() {
int x; int y = 9;
for(int x = 1; x < 20; x++) {
if (x <= 10) {
cout << x << " ";
}
else {
cout << y-- <<" " ;

}
}
}
// Output: 1 2 3 4 5 6 7 8 9 10 9 8 7 6 5 4 3 2 1

Answer 11

a@a@a although is related you should make your own question.

Btw mine in C
i;f(){for(i=8;i--;)printf("%d %d ",9-i,i+2);}

https://code.sololearn.com/c4CKbw0lM3gh/?ref=app

Answer 12

How toPrint FOR loop.
Output: 2 9 3 8 4 7 5 6 6 5 7 4 8 3 9 2

Answer 13

use nested For loops