Why cout<<x+1 is not giving answer??

Question

code of solo - https://www.sololearn.com/learn/CPlusPlus/1614/

code of my -
https://code.sololearn.com/cUrAQ428uefy/?ref=app

Answer 1

You don't get any output here, as your loop is an infinite one. The 'x' remains to be 5 and never becomes 6. So you need to assign it thr new value if you want the loop to end.

Use the preincrement operation:

#include <iostream>
using namespace std;

int main()
{int x=5;

while(x<9)
cout<<++x;

return 0;
}

Answer 2

thanks..for helping 😍😍

Answer 3

@procpp i have mentioned my written code

Answer 4

It's because you are not increasing the value of x in the bucle, you join in a infinite loop.
Write:
cout << x++;
and it will work.

Another way is to do (inside the while bucle):
cout << x;
x += 1; // (or x++;)

Answer 5

@Misa Amane
You may, but without the x++, ++x or x+=1, the loop executes forever.

Answer 6

Umm, where exactly? Can you share the code? Maybe you missed the 'int x' part?

Answer 7

If x is not a function,cout<<x+1 will output only "x+1"