Why i am getting this error

Question

What is missing??

package com.helloworld;
import java.util.Scanner;
public class main {

public static void main(String[] args) {

System.out.println("Please input the string:");
Scanner b = new Scanner(System.in);
System.out.println("Please input the number of times to repeat the string");
Scanner a = new Scanner(System.in);

for(int i=a; i>0; i--)
{
System.out.println(b.nextLine());
}

}
}

Answer 1

Got it!

package com.helloworld;
import java.lang.String;
import java.util.Scanner;
public class main {

public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("Please input the string:");
String string = scanner.nextLine();
System.out.println("Please input the number of times to repeat the string");
int integer = scanner.nextInt();

for(int i=integer; i>0; i--)
{
System.out.println(string);
}

}
}

Answer 2

you didnt take any strings from user,you just created the object of scanner.
take that and put in a string variable
then try your code

Answer 3

Try to convert the variable a into an integer first before you use it in the loop.

Answer 4

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {

Scanner a =new Scanner(System.in) ;
System.out.println ("enter your string");
String s=a.next() ;
System.out.println("your string is: "+s);

System.out.println ("how many repeats you want?");
int b=a.nextInt();
System.out.println (b);
for(int i=0;i<b;i++){
System.out.println(s);
}

}
}
😑 I WAS WRITING THIS 😂😢

Answer 5

a.nextInt() in for loop maybe?

Answer 6

blazingmagpie
i think in that case,user has to enter the string for many timez

Answer 7

did it work?

Answer 8

It worked, i got the soln.