C# help understanding reverse numbers

Question

int original, reverse = 0;
Console.Write("Enter a Number: "); // input 123 for test
original = int.Parse(Console.ReadLine());
while (original != 0) // condition to be met before stopping i.e. original = 0
{ // 2nd pass: 12 != 0 = true, continues while loop
// 3rd pass: 1 != 0 true, continues while loop
// 4th pass: 0 != 0 false, stops while loop
reverse *= 10; // equal to: reverse = reverse * 10; 0 * 10 = 0 = reverse
// 2nd pass: 3 * 10 = 30 = reverse
// 3rd pass: 2 * 10 = 20 = reverse
reverse += original % 10; // equal to: reverse = reverse + original % 10; 0 + 123 = 123 / 10 remainder = int 3 = reverse
// 2nd pass: 30 + 12 = 42 / 10 remainder 2 = reverse
// 3rd pass: 20 + 1 = 21 / 10 remainder 1 = reverse
original /= 10; // equal to: original = original / 10; 123 / 10 = int 12 = original
} // 2nd pass: 12 / 10 = int 1 = original
// 3rd pass: 1 / 10 = "int" 0 = original
Console.WriteLine("Reverse of Entered Number is: " + reverse); // how does this output 123 rather than just 1

I can grasp at the concept of the previous values of reverse accumulating during the iterations of the loop
but why doesnt WriteLine() also output the string "Reverse of Entered Number is: " 3 times? I know it somewhat happens if I enter it in the loop body but the reverse output is still: blah blah blah: 3 // I understand this
why doesn't this happen when WL() is outside----> " " : 32 // should'nt this be 2?
"

Answer 1

Avoid commenting like this, codes are self explanatory lines if you want to say something about a snippet means add them on top of the method no need to comment through the lines