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Why is bool([()])==True but bool(([]))==False ?
My question is based on a challenge. Does anybody have an explanation for this behaviour?
4 Réponses
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Because 1st bool means list object with tuple value in it i.e [ () ] . Although tuple is empty, it doesn't matter because bool check whether list [] contain something. This leads to True.
2nd bool is false because (( [] )) evaluate to simply [] cuz in case of (( something )) , parenthesis are simply code block. Hope it helps :)
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@Sylar & Davy:
Thank you both for your explanations! :-)
I have just found out that it is possible to get True in both cases, if you write the 2nd case like:
print(bool(([],)))
Mind the comma!
Then it is not just a pair of brackets but a tuple.
It is the same problem with (3) and (3,).
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The first one is a list containing an ( empty) element, making the list not empty, the second one is an empty list.
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Thanks. I was just wondering how that would work!