conditional statement

Question

give a positive integer n , do the following :
if 1 =<n=<9 then print the lowercase English word corresponding to the number (e.g; one for 1 , two for 2, ets)
if n>9 print greater than 9

Answer 1

I'd use this because it is simple to understand:
switch (n) {
case 1:
cout << "one";
break;
....
default:
cout << "greater than 9";
break;
}

if (n==1) cout << "one";
else if (n==2) ...
works too.

Answer 2

switch (n) {
case 1:
cout << "one";
break;
....
default:
cout << "greater than 9";
break;
}

if (n==1) cout << "one";
else if (n==2) ...
works too.