Some confusion in below code

Question

def apple():
print('in apple')
def mango():
print('in mango')

b=input('enter the num: ')
print(b)
if b==0:
apple()
else:
mango()

output

enter the number: 0
0
in mango

y in mango it shld be in apple right y input function taking as an string

Answer 1

Because variable 'b' is storing a String, not an int. You'll just want to convert the input to an int data type instead of a string type.

b = int(input('enter the num: '))

^int() is a function that'll convert it to an int. Just wrap your input statement inside of the int() function.

When you store it as a string and do no convert it, your IF check is seeing if it's equal to 0. Since a string isn't a number, it'll return false and execute the ELSE statement, which is to call the mango() function.

Hope that helps.

FULL CODE:

def apple():
print('in apple')
def mango():
print('in mango')

b = int(input('enter the num: '))
print(b)
if b == 0:
apple()
else:
mango()

Answer 2

Tnx, so input function returns only a string??

Answer 3

You're welcome, Pradeep.

Yes, by default it's going to return a string value unless you specify otherwise.

Answer 4

ok got it