please explain and obtain output of this array.

Question

int b[]={1,4,9,5,7};
int sum=0;
for(int i=0;i<5;i++){
if(i%2==0){
sum+=b[i];
}
cout<< sum;

Answer 1

when i =0 sum=0+1
when i =1 but 1%2 is not equal to zero
when i= 2 sum = 1+9
when i = 3 but 3%2 is 1 which is not zero
when i = 4 sum = 7+10
then It comes out of loop and sum= 17 is printed

Answer 2

write the size in the array b as 5

when the value of i is even then at each even value of array is added in sum

when i=0
sum = 0+1;

when i=2
sum =1+9;

when i=4
sum =10+7;

the output is 17

and add one more curly Bracket before cout

Answer 3

there is an open bracket that has not been closed. the "for" one. to be able to compile it remove the opening parenthesis of "if" or put a closed one before the cout.

Answer 4

You have to structurate your code to be more ease comprensible.

Answer 5

4%2 is also 0.so why not it get included?