Another problem

Question

int a,b,c,d, e=11;
a=b=c=d=0;
do{
e = e+1;
a = a+1;
if(a>=2) b = b+1;
if(b>=2) c = c+1;
if(c>=2) d = d+1;
if((a&&b)&&(c&&d)){
printf(" %d",e);break;
}
}while(1);
//end

didn't understand the last if statement, if anyone can please explain.

Answer 1

logical & operator returns true for any values other than 0
for eg.:-
1&&0 = 0 (false)
0&&0 = 0 (false)
1&&1 = 1 ( true)
2&&3 = 1 (true)
5&&7 = 1 (true)
n1&&n2 = 1 (true) ; where. n1,n2 ≠ 0

https://www.sololearn.com/learn/CPlusPlus/1619/?ref=app

Answer 2

yes sorry it will output 15
1st time the condition of last if will be false then 2nd time it will be true
it will break after printing 15
did u got the idea about last if statement

Answer 3

a = 0 + 1 = 1
b = c = d = 0
since all if has false condition
therefore in last if
if ((1&&0)&&(0&&0)) {
printf("something");
break; }
condition false
nothing happens...
because of while(1)
results in infinite loop

Answer 4

this outputs 15. not infinite loop

Answer 5

sorry i don't understand how if(1&&0) works. can you please explain?