How to fix this error? Fatal error: Cannot use temporary expression in write context in C:\Program Files\index.php on line 1506

Question

Please help me...
I have an error inside for loop.

$myArray=array();
$x=0;
$result='';

sc_lookup(ds,"SELECT latitude,longitude FROM heatmap");

for($i=0;$i<count({ds});$i++){
myArray[0][]= "new google.maps.LatLng(".{ds[$i][0]} .",". {ds[$i][1]} .")"; //error in this line
}

$result = json_encode($myArray);

Answer 1

As i can see, you only want to store the constructor string in the array?

Your problem is, that ds is a constant and since PHP7 Expressions of type (...)[42] and [...][42] (and other cases where some dereferencing operation is applied to a non-variable) are now parsed as a variable (rather than expr_without_variable, as it was previously).

This means that the expression will behave correctly in empty(). E.g. empty([]['a']) will no longer throw an undefined offset notice. Furthermore it is now possible to assign to expressions of this kind, for example (new Foo)->bar = 'baz' is now possible (thought doesn't make much sense unless Foo implements __set).

well, try following:

$_ds = ds;
for($i=0;$i<count({$_ds});$i++){
array_push(
$myArray[0],
"new google.maps.LatLng({$_ds[$i][0]},{$_ds[$i][1]})"
)
}

// A better, nicer and cleaner approach would to transform your for- into a foreach loop.

Answer 2

No its not working, again the same error occurs