[Challenge] [PL,java,Py,RB,js] Shorten this code !

Question

[Perl]
This code has 34 char, can you shorten it under 34 char?
AUTOLOAD {
$p=@{$_[0]};
$p == 3 ? 0 : $p % 2
}
Detail : @_ is array, and check the size.

[Java]
int f(int[] p) {
return p.length!=3?p.length%2:0;
}

[Ruby]
def f p
y=p.size
y==3?0:y%2
end

[Python]
def f(p):
x=len(p)
return 0 if x==3 else x%2

[JS]
f=p=>p.length==3?0:p.length%2;

Answer 1

I can shorten your Python version, a little bit:

[Python]
def f(p):
x=len(p)
return x%2
- (x==3)

I'm new to Perl! Does this work? If so, it's shorter.

AUTOLOAD {
$p == 3 ? 0 : @{$_[0]} % 2
}

Answer 2

how this can be work? (x!=3) * x%2

Answer 3

Apologies, my python code had a bug. It should have been x%2 - (x==3)

Explanation:

The result is always length % 2 (odd numbered lengths return 1, even numbered lengths, 0), except for when length is 3, which should give 0, instead of the usual 1.

(x==3) either equates to 0 or 1. 1 for when x is equal to 3, and 0 at any other time.

x%2 - (x==3)

Table of evaluated expressions to explain:

x, x%2, (x==3), x%2 - (x==3)
0, 0, 0, 0
1, 1, 0, 1
2, 0, 0, 0
3, 1, 1, 0
4, 0, 0, 0
5, 1, 0, 1
6, 0, 0, 0
7, 1, 0, 1
8, 0, 0, 0
9, 1, 0, 1

Answer 4

(x!=3) * x%2 also can be work in my testcase :D

Answer 5

bump this post