Why the output of b is 16 not 18

Question

#include <stdio.h>

int main() {
int a[5],i,b=16;
for(i=0;i<5;i++)
a[i]=2*i;
f(a,b);
for(i=0;i<5;i++)
printf("\n%d",a[i]);
printf("\nb=%d",b);
return 0;
}
f(int *x,int y)
{
int i;
for(i=0;i<5;i++)
*(x+i)+=2;
y+=2;
printf("\ny=%d",y);
}

Answer 1

You initialize b to 16 and never change its value.
Remember the difference between int *x and int x when using them as arguments for functions. int x does not change that variable, in this case, b.
Does this make sense?